Ey ppl!
I'm gonna be taking a break from LF for about a week or two. I've got 4 mid term exams coming up in the next couple of weeks.
One of them is tomorrow for maths. (2nd hardest)
The next day is for English (2 hour exam for an essay on a book).
Next week, an exam for Specialist maths (the hardest maths).
And then following that week, an exam for physics (the topic of sound).
Yep, that's why I need the time off to study and have no life. :(
While I'm gone, wish me luck!! (I'm gonna need it!!), be good, behave, don't talk to strangers and take it easy. See you all soon.
Well, time to go back to studying.
Cheers. :cheers:
Good luck dude!
Your gonna need it...:D
Pftsh! I had three just last week and I was still here. :xp:
Atleast you guys can go to school, and actually get somewhere, instead of being Arrested, suspended (possibley expelled) and living 3 weeks in your basement waiting to get back into school >_> I mean, Yeah, good luck!
Originally posted by Boba Rhett
Pftsh! I had three just last week and I was still here. :xp:
That's cos you're the admin. If you're not here, the forums turn upside down, lol.
I also need very high scores to get into the course I want to do. That's why I'm not gonna have too much free time.
Anyway, thanks guys, now it's back to studying Vectors.
good luck to you :cheers:
just remember...
All work and no play makes jack a dull boy. All work and no play makes Jack a dull boy. All work and no play makes Jack a dull boy. All work and no play makes Jack a dull boy. All work and no play makes Jack a dull boy. All work and no play makes Jack a dull boy. All work and no play makes Jack a dull boy. All work and no play makes Jack a dull boy. All wrok and no ploay makes Jack a d ll boy. All work and no play makes Jack a dull boy. All work and no play makes Jack a dull boy. All work and no play makes Jack a dull boy. All work and no play makes Jack a dull boy. All work and no play makes Jack a dull boy. All work and no play makes jack a dull boy. Allwork and no play makes jack a dull boy. All work and no play makes jack a dull boy. All work and no play Makes Jack a dull boy. All work and no play Makes Jack a dull boy. All work and no play makes Jack a dull boy. All work and no playb makes Jack a dull boy. All work and no play makes Jack a dullboy. All work and no play makes Jack a dull boy. All work and no play makes Jack a dull boy. All work and no play makes Jack a dull boy. All work and no play makes Jackk a dull boy. All work and no play makes Jack a dull boy. All work and no play makes Jack a dull boy. All work and no play makes Jack a dull boy. All work and no play makes jack a dull boy. All work and no play makes Jack a dull boy. All work and no play amakes Jack a dull boy. All work and no play makes Jack a dull boy. All work and no play makes jack a dull boy. All work and no play makes Jack a dull boy. All work and no play makes Jack adull boy. All work and no play makes jack a dull boy. All work and no play makes Jack a dull boy. All work and no play makes Jack a dull boy.
*goes to get an axe*
you know what you need? first of all, a pair of scissors, a jar of mayonaise, one copy of the oxford dictionary, and a mexican named pedro.... i mean... dammit. i got nothing. good luck!
o/
P.S. the above is a little man going High 5. the reply to this is \o, so none of you ask bad questions.
:D
:rofl: ROFLMAO!!! :D:D Thanks heaps guys for the laughs.
Originally posted by access_flux
you know what you need? first of all, a pair of scissors, a jar of mayonaise, one copy of the oxford dictionary, and a mexican named pedro.... i mean... dammit. i got nothing.
No, wait! You're onto something there! :eek:
My exams are starting on 1st next month.
Good Luck, dude!
(Wish me luke, i mean, luck too)
Thanks for it all ppl! And good luck to you too sabertooth!
God, had the maths one today (the second hardest one). Wasn't too bad, but I'm more worried about the hardest maths one. Are there any mathematicians out there? Can someone please explain to me how the hell this question works?!?
If z = x + yi and z = (-5 +12i), then the values of x and y respectively are:
A: -3 and 2
B: -2 and 3
C: 3 and 2
D: -3 and -2
E: 2 and 3
The correct answer is E, but how the hell does it work?!?! Can someone please explain this concept? This is confusing me and making me dizzy! :confused:
Cheers.
That maths is too high for my standard.
I don't get the question itself, let alone the answer!
z = x + yi
&
z = (-5 +12i),
1. Ok, I think I remember this. The SQRT of (-5 +12i) is worked out by first breaking down the numbers "-5" and "12" to -2*3 and 2*2*3. Then you take the pairs that are in those numbers and move them to the left side. Look at what they are! 2 and 3! Coincidence? I think not! We still have a -2 in the SQRT bracket though. But a - SQRT cannot exist so it is an imaginary number, which is what the, "i" represents. So that -2 turns into an i and is moved over to the left side as well
So,
z = x + yi
or
SQRT of (-5+12i) = 2 + 3i
Eh, I most likely have that wrong... but oh well, I can't remember and I tried. :D
Holy Crap Rhett!! That looks pretty damn good! :thumbsup:
I understand what you mean by the 'breaking down'. Of the integers.
Eg: -12 = 4*-3
Square root of negative 12: 2(sq}(-3)
= 2(3)i
That makes some more sense, thanks heaps Rhett :).
EDIT: Another question. i as we know is an imaginary number. My question is that if i^2 = -1, which is a real answer, is i therefore entirely imaginary/impossible? There must be some realistic aspects to i. What's your opinion? Am I right or do I need a break :S. Cheers again to Rhett and everyone.
They aren't really "imaginary", it's just that they do not exist in the real number set. Sometimes the easiest/only way to compute something, even if you start out with real numbers and the answer is a real number, is by using imaginary numbers.
They're used in conjunction with real numbers to spit out a real number, get it? Even fractions do this in one way or another.
The only direct usage for them I can think of is when measuring currents and things like that but as I explained in the previous paragraph, they're very useful in that particular way.
Thanks heaps for clarifying me Rhett :thumbsup:.
Such a complicated maths question... I don't know how to do. :P
Oh, good luck for your exams! Don't need to study so hard, actually... I didn't really study for my exams and still managed to get a few A's! :D
Good luck on your exams! Just make sure that you don't worry too much for nothing, but you should study some. Oh and here's a good math tip: The billionth digit of Pi is 9. :thumbsup:
I have a calculus 2 midterm tonight. I shouldn't be hanging around here but I am not too worried about it.
Originally posted by the_raven_03
I have a calculkus 2 midterm tonight. I shouldn't be hanging around here but I am not too worried about it.
Good luck with that one man! It's on integration techniques isn't it? heh heh heh......
Originally posted by ET Warrior
Good luck with that one man! It's on integration techniques isn't it? heh heh heh......
Yes it is.
I've taken 3 exams in the last week, and one more on friday. So far the scores are...
70 on Calc 3
88 on Psychology
100 on Physics
Data structures in a couple of days. Meh.
Well I think I did very well on my calc exam tonight. I guess I will find out tomorrow.
I've got two weeks to study before I take the "Dakota Step" test. I took a practice Math test today, and got my *** beat by algebra equations.
Here's hoping this "FlyingDAWG" pulls an ace out of his hat by that time, or else going into the senior grade next year will look pretty bleak. :(
God, I had my maths one yesterday and my english one this morning. I don't think I did too badly at all. I'm looking for a very high 93% + score (hopefully). Now it's studying for Specialist Maths, Vectors (God that gets confusing). Damn, I've got a whole heap of physics to do as well on sound. Oh well, thanks again ppl! :)
Originally posted by ET Warrior
I've taken 3 exams in the last week, and one more on friday. So far the scores are...
70 on Calc 3
88 on Psychology
100 on Physics
Data structures in a couple of days. Meh.
Your Physics sure is good. I've had my Physics paper, I don't know almost all of the questions. x_x I'm sure to fail it.
Work hard
Play hard
Study hard
Good luck, you're gonna need it ;) Hope you pass
Play hard, study less, more A's confirmed. :D
Well, you said you'll need it.
Originally posted by Jedi Luke
Vectors (God that gets confusing).
No way man, Vectors are easy. PM me if you want any assistance with some problems.
Originally posted by ET Warrior
No way man, Vectors are easy. PM me if you want any assistance with some problems.
Thanks man :)! I will.
You dont need anyone's help, just sneak into the office or school comps and look at the paper, then ask someone to give you all correct answers and volia!
You'll be getting straight A's! :D
Hey ET, I've got a question regarding Vectors.....:)
Q.) Express each vector as a product of its length and direction.
(a) i + 2j - 2k
Ok, the answer to this question is: 3( (1/3)i + (2/3)j - (2/3)k )
I understand how you get the answer. Find the magnitude (which is of course a scalar quantity and does not affect the direction of vectors), of the vector quantities, then for each vector quantity, divide by the magnitude so expansion of the final expression is the original expression.
My problem basically is that I didn't understand what the question asked me to do, or what this answer means. Could you please explain it to me ET or anyone? Thanks :)
Well since you know how to find the magnitude, and divide by it I won't go into detail on how to do that, but now that you've divided your original vector by the magnitude you're left with a unit Vector (vector of length 1) pointing in the direction of the original vector. Unit Vectors can always be refered to as the direction of the vector.
And then the length of the vector is just the magnitude.
So displaying a vector as a product of length and direction is really just asking for the product between the magnitude and the unit vector.
Hope that helps.
Originally posted by ET Warrior
So displaying a vector as a product of length and direction is really just asking for the product between the magnitude and the unit vector.
Hope that helps.
Yes that definately makes much more sense how you've explained it. In multiplying the unit vector by its magnitude has to result in the original expression. Thanks heaps ET for you help. :thumbsup: :)
Originally posted by Jedi Luke
Thanks heaps ET for you help.
I live to serve. And do other stuff when I'm not serving.
Well I had my specialist maths assesment big test thing today. Wasn't too bad for the first section, but we're gonna finish part B and part C on monday. 20 minutes to go till the end of the lesson, he gave us part B, I had a look at it and boy it's gonna take a while to finish and it looks hard :(. Our teacher said for us to start it and have a look at it for over the weekend. I saw one question that looked tricky so looks like I'm gonna need help from ET, Rhett or anyone else that knows. Here it is:
(1 + itanx)^5 = (cis5x)/(cos^5x)
i is imaginary, ie root -1 as you know
assume x for theta (angle)
For the RHS equation, the denominator, cos^5x, is cos^5 , not 5x, so it's cos^5(x), just making sure no-one gets confused.
Basically, we need to proove this identity. The RHS is in fractional form (as you probably have guessed) but I can't put it as a fraction on the PC.
I'm too tired to think now, I'm busy studying standing waves and 2 dimensional interference........soo tired.....zzzzzzzz
Any help?
Thanks heaps everyone! :)
Originally posted by Jedi Luke
(cis5x)/(cos^5x)
Is that supposed to be Cos(5x) in the numerator?
Originally posted by ET Warrior
Is that supposed to be Cos(5x) in the numerator?
No that is supposed to be cis(5x)
Cis is the Polar form expression of the cartesian form expression.
cis is (cos(x) + i sin(x))
cis is short hand for: cos theta plus i sin theta. (that's the full cis expression).
i (root -1) is multiplying with sin(x). (x) is of course the angle.
You probably new all that ET and was just double-checking to be sure but just in case and for others, that's what it is.
Thanks.